Answers & Explanations: SNAP Official Mock Test 2020

Section – I: General English

Q.1) Option (A).

See But the world Fish was describing, where no one could live–tweet the lectures, let alone post the talks for worldwide distribution, now seems sepia–toned. It is clear that the phrase ‘sepia–toned’ here refers to the time that is gone and will not come back. It refers to the era that is over. 

Q.2) Option (B).

The passage is about how the way the new forms of reaching out to an audience is changing the earlier models. See These new, or at least newish, forms are upending traditional hierarchies of academic visibility and helping to change which ideas gain purchase in the public discourse. Hence b. 

Q.3) Option (D).

Options a, b and c can be derived from the passage as enough information is present to support them. D cannot be inferred from the passage. 

Q.4) Option (A).

The second part of the sentence talks about the last date of submission getting impacted. That means extend or stretch can fit there, though extend is a better choice between the two as stretch is slightly negative in meaning and here the context is positive. Enjoyed does not fit the first blank contextually. Hence option is the most appropriate. 

Q.5) Option (C).

The sentence talks about high cut–off leaving admission seekers with no real choices. Hence option c fits the best as it talks about admission seekers being forced and thereby settling for lesser known colleges. 

Q.6) Option (D).

Is aware should be are aware as the helping verb is here refers to members and therefore should be plural. 

Q.7) Option (C).

The 5th sentence says in the budget and therefore fits well after 3. Hence 35 is a pair. The rest of the sentences explain how the bifurcation is a good idea. 

Q.8) Option (B).

Platitudes means a remark or statement that has been used too often to be interesting or thoughtful. The second part of the sentence indicates that the word that comes in the gap should talk about something often repeated. 

Q.9) Option (B).

In sentence b, who refers to others which is a plural word and hence requires a plural verb. Therefore, use of uses is wrong. It should be use. 

Q.10) Option (C).

Punctilious means showing great attention to detail or correct behaviour. Hence c is the most appropriate choices. 

Q.11) Option (D).

Magnum Opus means a work of art, music, or literature that is regarded as the most important or best work that an artist, composer, or writer has produced.

Q.12) Option (A).

Furlough means leave of absence, especially that granted to a member of the services or a missionary. Hence a. 

Q.13) Option (B).

4 introduces the topic by talking about the dismemberment of the federation, 2 follows it by telling the reader which federation we are talking about, (that was Yugoslavia). 5 tells us the reason people think it got dismembered for, but 3 and 1 tell us the actual reason. 

Q.14) Option (B).

The sentence talks about indecision and how free men feel the need to choose a certain kind of ruler without caring about democracy. As the men are indecisive, they are likely to choose someone who does not value freedom and democracy. Hence autocratic is the correct choice. 

Q.15) Option (B).

Inordinate and Huge both mean unusually or disproportionately large. Considerable means notably large in size, amount but not excessive. Hence it is the word that does not match with inordinate and huge. 

Section – II: Analytical & Logical Reasoning 

Q.16) Option (D).

1. clearly, this is ruled out
2. It may be possible in one case but is not certain

Hence, neither conclusion follows

Q.17) Option (A).

Read the numbers upside down.

These are 91, ___, 89, 88

So, missing number is upside down of 90 i.e. 06

Q.18) Option (B).

The first two digit of the middle number is sum of all four outer numbers and the third number is always 2. Like in first figure, 5 + 7 + 9 + 3 = 24, in second figure, 12 + 13 + 14 + 11 = 50. 

So, 7 + 10 + 21 + ? = 66

Or, ? = 28

Q.19) Option (C).

Wherever the trains meet, the point will be at a fix distance from Chennai. So, both the trains will be equidistant from Chennai

Q.20) Option (C).

Here, the counting of alphabets is starting from ‘M’

So, M = 1, N = 2, O = 3, P = 4, Q = 5 and so on so forth

So, R = 6, E = 19, S = 7 and T = 8

So, REST = 6 – 19 – 7 – 8 

Q.21) Option (C).

Suppose player 1 defeats all other players. So, he will play one match with each of the other 29 players. So, there will be 29 matches.

Even if make other cases like first, 15 pairs will play 15 matches. Now out of 15 winners, 14 by play 7 matches. Now, these 7 winners along with the 1 person left out of 15 will play 4 matches. These 4 winners will play 2 matches and finally 1 match to determine the winner.

So, total matches = 15 + 7 + 4 + 2 + 1 = 29

Note: In these type of tournaments, total number of matches is always (n – 1), where n is the number of players/teams.

Q.22) Option (B).

Let A be the starting point and B be the final position. So, distance AB = 20 + 15 = 35 m and the direction is East.

Q.23) Option (C).

Each letter – 1 and the reverse

So, HONEY = GNMDX

And then reverse = XDMNG

Q.24) Option (B).

5 × 2 – 1 = 9

9 × 2 – 2 = 16

16 × 2 – 3 = 29

29 × 2 – 4 = 54

54 × 2 – 5 = 103

103 × 2 – 6 = 200

So, 7th term will be 200

Q.25) Option (B).

Oil will put off the flame as it is heavy and will drop on the flame.

Patrol will burn

Water will put off the flame

Q.26) Option (C).

The position of White and Brown is not known. But in either case, they will be opposite to each other.

Q.27) Option (D).

The schedule will be:

Q.28) Option (A).

Case 1: Let first statement is true.

So, cash is not in First carton. Now, second statement must be false. So, cash is in second carton which makes the third statement true. But only one statement is true. So, this case is not possible.

Case 2: Let the second statement is true. So, cash is not in second carton. Which makes third statement false. First statement must be false. So, cash is in first carton. So, in this case, the first statement is false, second statement is true and third statement is false. And the cash is in first statement

Case 3: Let the third statement is true. So, cash is in second carton. But it makes first statement also true. Which is not possible. 

Hence, only case 2 is valid and the cash is in first carton.

Q.29) Option (D).

The triangle joining his house, office and gym is an equilateral triangle. So, triangle joining his office, gym and point A is also an equilateral triangle. So, Distance between A and gym is 4 km

Also, the triangle office–gym–B will be isosceles triangle. So, Gym–B = 4 km

So, total distance = 4 + 4 + 4 = 12 km

S.30–31) Directions for Solutions: 

There are two cases:

Case 1:

Case 2:

But in first case, there are 3 students between Rina and Tina. So, this case is ruled out.

Hence

Q.30) Option (B).

Q.31) Option (C).

Q.32) Option (D).

Option ‘a’ will be represented like:

Option ‘b’ will be represented like:

Option ‘c’ will be represented like:

Hence, Option ‘d’ is correct

Q.33) Option (B).

After 4 turns, he will be at the same direction. So, after any multiple of 4, he will be at the same direction.

So, in 3824 turns, he will be at the same direction

In next 2 turns, he will move 900 clock–wise 2 times.

So, he will face Mahesh

Q.34) Option (C).

Baby Pig is called Farrow

Baby Lion is called Cub

Baby Bear is also called Cub

Q.35) Option (D).

After unscrambling we will get

1. SUMMER
2. WINTER
3. SPRING
4. CLOUD

First three are seasons

So, CLOUD is different

Q.36) Option (C).

The centre of the circle at the top will lie outside the base circles (in the middle of the three) and the centres of all the base circles are on the top circle, so the radius will be greater than r

Q.37) Option (B).

2 × 3 + 5 = 11

(–5) × 2 + (–2) = –12

(–10) × 6 + (–10) = –70 

Q.38) Option (A).

Z – Y = 1

Y – X = 1

X – V = 2

V – S = 3

1, 1, 2, 3 is a Fibonacci series

So, next term is 2 + 3 = 5

So, S – ? = 5

Or, ? = N

Q.39) Option (C).

Gannu is brother of Molu and Polu. So, Golu’s maternal uncle is Gannu.

Q.40) Option (B).

To show the correct time, the clock must gain 1 minute

The watch gains 3 minutes in 48 hrs

So, it will gain 1 minute in 16 hrs

So, it will show correct time at 5 a.m. on Wednesday

Section – III: Quantitative, Data Interpretation & Data Sufficiency

Q.41) Option (A).

Average price per litre minus the taxes = (35+34+35.5+37+37.5+38)/6 = 217/6

So, average amount of tax collected = 125% of 217/6 = 45.2

Q.42) Option (A).

Let the sides are 2x and 7x respectively

So, perimeter = 2(L + B) = 2(7x + 2x) = 18x

So, 18x = 360

Or, x = 20

So, length and breadth are 140 and 40 respectively

Alternate Approach: Only option a has the length and breadth in the ratio 7 : 2

Q.43) Option (D).

Let the work = 30 units

So, A can do 3 units/day and B can do 2 units/day

So, work done in 4 days = 4 × (3 + 2) = 20 units

So, fraction of work done = 20/30 = 2/3

So, Work left = 1/3

Alternate Approach:

A and B together can finish the work in days

So, in remaining 2 days, work will be done

Which is left.

Q.44) Option (A).

Let the distance = 200 km

So, time excluding the halts = 200/50 = 4 hrs

And time including the halts = 200/40 = 5 hrs

So, stoppage time in 5 hrs = 1 hr

So, in 1 hr = 1/5 hr = 12 minutes

Alternate Approach:

Ratio of speed = 5 : 4

So, ratio of time = 4 : 5

So, 1 hrs stoppage in 5hrs

Q.45) Option (D).

In the given word, there are 2 A and 2 T

The letters of the word can be arranged in 9!/2!2! = 90720

Q.46) Option (D).

Let x, y and z be the number of items purchased by Nisha of price Rs. 5, 2 and 1 respectively

So, 5x + 2y + (z + 3) = 20 

Or, 5x + 2y + z = 17 … (1)

Now, x, y and z are at least 2

Case 1:

If x = 3, 2y + z = 2

But the minimum value of 2y + z will be 6

So, this case is not possible

Case 2:

If x = 2, 2y + z = 7

So, y = 2 and z = 3

No other case is possible

So, total number of items = 2 + 2 + 3 + 3(extra) = 10 

Q.47) Option (B).

The diagram will look like:

So, Only B : Only C = 5 : 10 = 1 : 2

Q.48) Option (D).

x/5=y

y% of 20 = y/5 = x/25

And, (x/25)*100 = 4% of x

Q.49) Option (D).

Number of green dyes = 5

Number of red dyes = 3

Number of blue dyes = 4

Number of combinations with any number of red dyes = 23 = 8

Number of combinations with at least one green dye = 25 – 1 = 31

Number of combinations with at least one blue dye = 24 – 1 = 15

Total number of ways = 8 × 31 × 15 = 3720

Alternate Approach:

Total number of cases = 212 = 4096

Answer must be less than this but not as low as 31 or 60

Q.50) Option (A).

Marathi books can be arranged among themselves in 5! = 120 ways

English books can be arranged among themselves in 3! = 6 ways

Tamil books can be arranged among themselves in 3! = 6 ways

And these three groups can be arranged in 3! = 6 ways

So, total number of ways = 120 × 6 × 6 × 6 = 25920

Q.51) Option (B).

Total fund = 20 × 10000 = 2,00,000

Investment if risk management = 50% of 2,00,000 = 1,00,000

Investment in securities = 1,00,000

Gain by equities = 1% of 1,00,000 = 1,000

Gain by riskless securities = 7.8% of 1,00,000 = 7800

So, total gain = 1000 + 7800 = 8800

Gain per student = 8800/20 = 440

Gain % = (440/10000)*100 = 4.4%

Alternate Approach: As both investments are same, the average gain % = (1% + 7.8%)/2 = 4.4%

Q.52) Option (C).

Total number of words starting with M = 5! = 120

Q.53) Option (D).

For two years, 

= 23152.5

Alternate Approach:

For 3 years at SI, the interest would have been 15% of 20000 = 3000

So, at CI, interest should be slightly more than 3000 or amount more than 23000.

Option b is very high so option d is correct

Q.54) Option (A).

Let the income = 100x

So, amount spent on clothes = (2/(4+2+5))*55x = 10x

So, 10x = 5540

Or, x = 554

So, monthly income = 55400

Q.55) Option (B).

Let the price of fridge = 100. So, price of TV = 150

So, total price = 250

Required % = (100/250)*100 = 40

Q.56) Option (B).

Let the expenditure = 100

So, because of increase in price by 20%, the expenditure should have been 120.

But he wants to spend 5% extra i.e. 105

So, because of consumption, 120 should brought down to 105 

So, percentage decrease = (15/120)*100 = 12.5

Q.57) Option (D).

Radius of the largest semi–circle = 14

Radius for the smaller semi–circles = 3.5, 3.5 and 7

Q.58) Option (C).

When Anu covers 4000 m, Bina covers 3400 m

Also, when Bina covers 4000 m, Caira can cover 3800 m

So, when Bina covers 3400 m, Caira will cover (3800/4000)*3400 = 3230m

So, when Anu covers 4000 m, Caira will cover 3230 m

So, Anu can give Caira a startup of 4000 – 3230 = 770 m

Q.59) Option (A).

Let the number to be multiplied = x

So, 34x – 25x = 405

Or, x = 45

So, 34 × 45 = 1530

Q.60) Option (C).

Let the fixed charge = Rs. a and variable charge = Rs. b/km

So, a + 10b = 150 … (1)

And, a + 15b = 220 … (2)

So, a = 10 and b = 14

So, for 25 km, total fare = 10 + 25 × 14 = 360

Alternate Approach:

For increase of 5 km, fare increased by 220 – 150 = 70

So, for increase of 10 km, fare will be increased by 140

So, fare of 25 km = 220 + 140 = 360